![]() So,the for end to end delay for 8 cars is = 1 hr 34 min 48 sec The time taken by three toll booth to reach 8 cars = 3 x 96 = 288 secĮnd-to-end delay is = 1.5 hrs + 4 min 48 sec The time taken to reach 8 cars = 8 x 12 = 96 sec Repeat (a), now assuming that there are eight cars in the caravan instead of ten.Īnswer : the total transmission delay = 150/100 = 1.5 hrs The end-to-end delay is = 1.5 hrs + 6 min = 1 hr 36 minī. The time taken by 3 toll booth to reach 10 cars = 6 min ![]() So the time taken to reach 10 cars is = 120 sec or 2 min The time taken by each toll booth to reach a single car = 12 sec So the total transmission delay = 150/100 = 1.5 hrs Suppose the caravan travels 150 km, beginning in front of one tollbooth, passing through a second tollbooth, and finishing just after a third tollbooth. What is the end-to-end delay? Assume a propagation speed of 100 km/hour.Ī. Review the car-caravan analogy in Section 1.4. so,ġ packet = the end-to-end delay (d) = N(L/R) The general case of sending one packet from source to destination over a path consisting of N links each of rates R. Generalize this formula for sending P such packets back-to-back over the N links. Equation 1.1 gives a formula for the end-to-end delay of sending one packet of length L over N links of transmission rate R.
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